Réponse :
bonjour
factoriser
(8-3y)(y+5)+(8-3y)(y+6)=
(8-3y)(y+5+y+6)=
(8-3y)(2y+11)=(2y+11)(8-3y)
2y(y-3)+14(y-3)=
(y-3)(2y+14)=
2(y+7)(y-3)
y²(8-3y)+4(8-3y)=
(8-3y)(y²+4)=(y²+4)(8-3y)
-y(y-3)-y+3=
(y-3)(-(y+1))=
-(y+1)(y-3)
Explications étape par étape
