Réponse :
Bonjour,
2x – 5 < 3
⇔ 2x < 3 + 5
⇔ 2x < 8
⇔ x < 4
Donc S = ] -∞ ; 4 [
5 – 3x < 21 + x
⇔ –3x – x < 21 – 5
⇔ –4x < 16
⇔ x > –4
Donc S = ] –4 ; +∞ [
A = 2x – 5x(x + 4)
= 2x – 5x² – 20x
= –5x² – 18x
B = (3x – 7)(5x + 2)
= 15x² + 6x – 35x – 14
= 15x² – 29x – 14
8y – 4y²
= 2 × 4 × y – 4 × y × y
= 4y(2 – y)
a² – b² ⇔ (a – b)(a + b)
↓
49 – x²
= 7² – x²
= (7 – x)(7 + x)