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Sagot :

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résoudre [tex]\frac{2}{5x-5} = \frac{1}{2x-9}[/tex]

[tex]\frac{2}{5x-5} = \frac{1}{2x-9}[/tex]

[tex]\frac{5x-5}{2} = \frac{2x-9}{1} \\\frac{5x}{2} -2,5 = 2x -9\\5x-5=4x-18\\x = -18 + 5\\x = -13[/tex]

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