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Sagot :

POUKAY57

Réponse:

  1. [tex] (\sqrt{5 } + 1) {}^{2} = \sqrt{5 {}^{2} } + 2 \sqrt{5} + 1 ^{2} = 5 + 1 + 2 \sqrt{5 } = 6 + 2 \sqrt{5} [/tex]
  2. [tex]( \sqrt{5} - 1) {}^{2} = \sqrt{5} ^{2} - 2 \sqrt{5 } + 1 = 5 + 1 - 2 \sqrt{5} = 6 - 2 \sqrt{5} [/tex]
  3. [tex] \sqrt{6 + 2 \sqrt{5} } = \sqrt{( \sqrt{5} + 1) {}^{2} } = \sqrt{5} + 1[/tex]
  4. [tex] \sqrt{6 - 2 \sqrt{5} } = \sqrt{( \sqrt{5} - 1) ^{2} } = \sqrt{5} - 1[/tex]

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