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Sagot :

Bonjour !

a.

(5x + 7)(x - 3) - (x - 3)(x + 2)

= (x - 3) [(5x + 7) - (x + 2)]

= (x - 3)(5x + 7 - x - 2)

= (x - 3)(4x + 5)

b.

(x - 3)(2x - 5) + 2x - 6

= (x - 3)(2x - 5) + 2(x - 3)

= (x - 3) [(2x - 5) + 2]

= (x - 3)(2x - 5 + 2)

= (x - 3)(2x - 3)

c.

(x - 3)² + x - 3

= (x - 3)(x - 3) + 1(x - 3)

= (x - 3) [(x - 3) + 1]

= (x - 3)(x - 3 + 1)

= (x - 3)(x - 2)

d.

(x + 3)(x - 3) - 5(x - 3)²

= (x + 3)(x - 3) - 5(x - 3)(x - 3)

= (x - 3)[(x + 3) - 5(x - 3)]

= (x - 3)(x + 3 - 5x + 15)

= (x - 3)(-4x + 18)

= 2(x - 3)(-2x + 9)

J'espère t'avoir aidé. Bon courage !

Bonjour,

en gras le facteur commun

(5x+7)(x-3)-(x-3)(x+2) = (x-3)[(5x+7)-(x-2)] = (x-3)(4x+9)

(x-3)(2x-5)+2x-6 = (x-3)(2x-5)-2(x-3) = (x-3)(2x-5-(-3)) = (-3)(2x+8)

(x-3)²+x-3 = (x-3)(x-3)+1(x-3) = (x-3)(x-3+1) = (x-3)(x-2)

le dernier est un tout petit peu plus compliqué :

(x+3)(x-3)-5(x-3)² = (x+3)(x-3)-5(x-3)(x-3)

                           = (x-3)[(x+3)-5(x-3)]

                           = (x-3)(x+3-5x+15)

                           = (x-3)(-4x+18)

                           = 2(x-3)(9-2x)

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