[tex] {bc}^{2} = {15}^{2} = 225 \\ {cd}^{2} = {9}^{2} = 81 \\ {bd}^{2} = {12}^{2} = 144 \\ {cd}^{2} + {bd}^{2} = 81 + 144 = 225 \\ {cd}^{2} + {bd}^{2} = {bc}^{2} \\ l \: egalite \: de \: pythagore \: est \: verifiee \: le \: tringle \: bdc \: est \: rectngle[/tex]
Réponse:
Voila