Réponse :
1. f(1) = V1 = 1 => A ∈ f(x) ; f(4) = V4 = 2 => C ∈ f(x) ; V25 = 5 ≠ -5 => D ∉ f(x)
2. f(25) = 5 ; f(8) = V8 = 2V2 ; F(48) = V48 = 4v3
3. attention dom déf Vx = R+
Vx = 5 => x² = 25 => x = 5
Vx = 0 => x = 0
Vx = -2 impossible Vx ≥ 0
bonne soirée
Explications étape par étape
