Answered

Bonsoir, pouvez vous m'aider svp,
Développer l'expression suivante :
(5t + 2)² + (t + 3) (3t - 4)

et aussi,
il faut factoriser l'expression suivante :
(-8x + 8)² - 16

Merci !

Sagot :

MITCHALEXANDRINE2314

(5t + 2)^2 + (t + 3) (3t - 4)

=(5T×5T)+(5T×2)+(2×2)+(2×5T)+(T×3T)-(T×4)+(3×3T)-(3×4)

=25T^2+10T+4+10T+3T^2-4T+9T-12

=28T^2+10T+10T+4-4T+9T-12

=28T^2+20T+4-4T+9T-12

=28T^2+16T+4+9T-12

=28T^2+25T+4-12

=28T^2+25T-8

(-8x + 8)² - 16

=(12-8X)(4-8X)

DINA2712
Bonsoir :),

(5t+2)² + (t+3) (3t-4)=

[ (5t+2) (5t+2) ]+ [ (t+3) (3t-4) ] =

[ 5t x 5t + 5t x 2 + 2 x 5t + 2 x 2 ] + [ (t+3) (3t-4) ] =

25t² + 10t + 10t + 4 + [ (t+3) (3t-4) ] =

25t² + 20t + 4 + [ t x 3t + t x (-4) + 3 x 3t + 3 x (-4) ] =

25t² + 20t + 4 + [ 3t² + (-4t) + 9t + (-12) ] =

25t² + 20t + 4 + 3t² + 5t - 12 =

28t² + 25t - 8

———

(-8x + 8)² - 16 =

16 x (2x - 3) (2x - 1) =

16(2x - 3) (2x - 1)

Voilà ;)