factoriser

(x+1)^2-(2x+3)^2

merci d'avance


Sagot :

Bonjour

Factoriser

(x+1)²-(2x+3)²

= (x + 1 + 2x + 3) (x + 1 - 2x - 3)

= (3x + 4) (-x - 2)

Réponse:

x^2 +2x+1-(4x^2+12x+9)=-3x^2-10x-8