Bonsoir
Développer cette expression :
f(x)=(2x-1)²-(2x-1)(x+5)
f (x) = 4x² - 4x + 1 - (2x² + 10x - x - 5)
f (x) = 4x² - 4x + 1 - 2x² - 10x + x + 5
f (x) = 4x² - 2x² - 4x - 10x + 2x + x + 1 + 5
f (x) = 2x² - 13x + 6
Factoriser cette expression :
f(x)=(2x-1)²-(2x-1)(x+5)
f (x) = (2x - 1) [(2x - 1) - (x + 5)]
f (x) = (2x - 1) (2x - 1 - x - 5)
f (x) = (2x - 1) (x - 6)
Bonjour,
développement :
(2x-1)²-(2x-1)(x+5) = 4x²-4x+1-(2x²+10x-x-5)
= 4x²-2x²1-4x-10x+x+1+5
= 2x²-13x+6
factorisation :
(2x-1)²-(2x-1)(x+5) = (2x-1)(2x-1)-(2x-1)(x+5)
= (2x-1)[(2x-1)-(x+5)]
= (2x-1)(x-6)