Réponse :
Explications étape par étape
Bonjour
Factorisation :
f1(x) = (2x+3)(5x+1)-(2x+3)(-6x+2)
f1(x) = (2x + 3)(5x + 1 + 6x - 2)
f1(x) = (2x + 3)(11x - 1)
f2(x) = (2x-1)(5x+1)-(8x-4)(3x+2)
f2(x) = (2x - 1)(5x + 1) - 4(2x - 1)(3x + 2)
f2(x) = (2x - 1)(5x + 1 - 4(3x + 2))
f2(x) = (2x - 1)(5x + 1 - 12x - 8)
f2(x) = (2x - 1)(-7x - 7)
f2(x) = (2x - 1) * (-7)(x + 1)
f2(x) = (-7)(2x - 1)(x + 1)
f3(x) = (4x+1)(5x-2)-(10x-4)
f3(x) = (4x + 1)(5x - 2) - 2(5x - 2)
f3(x) = (5x - 2)(4x + 1 - 2)
f3(x) = (5x - 2)(4x - 1)
f4(x) = (2x+3)(5x+1)-(4x^2+12x+9)
f4(x) = (2x + 3)(5x + 1) - [(2x)^2 + 2 * 2x * 3 + 3^2]
f4(x) = (2x + 3)(5x + 1) - (2x + 3)^2
f4(x) = (2x + 3)(5x + 1 - 2x - 3)
f4(x) = (2x + 3)(3x - 2)
