Réponse:
f (1)= 1^2+3×1
f (1)=4
f (-10)= (-10)^2+3×(-10)
f (-10)= 100-30
f (-10)= 70
f(5/4)=
[tex]( \frac{5}{4} ) {}^{2} + 3 \times \frac{5}{4} [/tex]
f(5/4)=
[tex] \frac{25}{16} + \frac{15}{4} [/tex]
f(5/4)=
[tex] \frac{25 \times 4 + 16 \times 15}{16 \times 4} [/tex]
f (5/4)=
[tex] \frac{340}{64} [/tex]
f(5/4)= 85/16
