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Sagot :

[tex] \sqrt{ \frac{15}{45} } = \sqrt{ \frac{1}{3} } = \frac{1}{ \sqrt{3} } = \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{3} }{3} [/tex]

[tex] \sqrt{ \frac{50}{2 \sqrt{5} } } = \sqrt{ \frac{50}{10} } = \sqrt{ \frac{25}{5} } = \sqrt{5} [/tex]

[tex] \sqrt{ \frac{121}{49} } = \frac{ \sqrt{121} }{/sqrt49} = \frac{11}{7} [/tex]

bonne continuation

y'a un petit bug le /squart signifie √

donc √121/√49 = 11/7

bjr

G = √(15/45)    [on simplifie par 15 : 15 / 45 = 1/3

G = √(1/3) = 1/√3 = √3/3

H = 50 /(2√25)      [√25 = 5]

H = 50 /(2 x 5) = 50/10 = 5

I = √(121/49)                [121 = 11² ; 49 = 7²]

I = √121/√49 = 11/7    

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