Sagot :
[tex] \sqrt{ \frac{15}{45} } = \sqrt{ \frac{1}{3} } = \frac{1}{ \sqrt{3} } = \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{3} }{3} [/tex]
[tex] \sqrt{ \frac{50}{2 \sqrt{5} } } = \sqrt{ \frac{50}{10} } = \sqrt{ \frac{25}{5} } = \sqrt{5} [/tex]
[tex] \sqrt{ \frac{121}{49} } = \frac{ \sqrt{121} }{/sqrt49} = \frac{11}{7} [/tex]
bonne continuation
y'a un petit bug le /squart signifie √
donc √121/√49 = 11/7
bjr
G = √(15/45) [on simplifie par 15 : 15 / 45 = 1/3
G = √(1/3) = 1/√3 = √3/3
H = 50 /(2√25) [√25 = 5]
H = 50 /(2 x 5) = 50/10 = 5
I = √(121/49) [121 = 11² ; 49 = 7²]
I = √121/√49 = 11/7