Sagot :
bjr
A = (3/5)² = 3²/5² = 9/25
B = (-1/4)³ (nombre négatif, exposant impair, signe -)
= - 1³/4³ = - 1/64
C = - (-3/10)⁵ = - ( -(3⁵/10⁵) ) = + 3⁵/10⁵ = 243/100 000
D = (1/3)⁻² = 1/(1/3)² (a⁻² = 1/a²)
= 1/(1²/3²)
= 1/(1/9)
= 9 (1/(a/b) = b/a)
E = (5/2)⁻³ = 1/(5/2)³ = 1/(5³/2³) = 2³/5³ = 8/125
F = (-1/2)⁻⁴ = 1/(-1/2)⁴ = + 1/(1/2⁴) = 2⁴ = 16
Réponse :
Explications étape par étape
Bonjour
Écris chaque nombre sous la forme d’une fraction :
[tex]A = (\dfrac{3}{5})^{2}[/tex]
[tex]A = \dfrac{3^{2}}{5^{2}}[/tex]
[tex]A = \dfrac{9}{25}[/tex]
[tex]B = \dfrac{(-1)^{3}}{4^{3}}[/tex]
[tex]B = \dfrac{-1}{64}[/tex]
[tex]C = \dfrac{-(-3)^{5}}{{10}^5}[/tex]
[tex]C = \dfrac{-(-243)}{100 000}[/tex]
[tex]C = \dfrac{243}{100 000}[/tex]
[tex]D = \dfrac{1}{3}^{-2}[/tex]
[tex]D = \dfrac{1^{-2}}{3^{-2}}[/tex]
[tex]D = \dfrac{3^{2}}{1^{2}}[/tex]
[tex]D = 9[/tex]
[tex]E = (\dfrac{5}{2})^{-3}[/tex]
[tex]E = (\dfrac{2}{5})^3[/tex]
[tex]E = \dfrac{2^{3}}{5^{3}}[/tex]
[tex]E = \dfrac{8}{125}[/tex]
[tex]F = (\dfrac{-1}{2})^{-4}[/tex]
[tex]F = (-2)^{4}[/tex]
[tex]F = 16[/tex]