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Sagot :

Réponse :

ex12

{a0 = 1

{an+1 = 10 an/(an + 3)  pour tout entier naturel n

a1 = 10a0/(a0 + 3) = 10 x 1/(1+3) = 10/4 = 5/2 = 2.5

a2 = 10a1/(a1 + 3) = 10 x 2.5/(2.5+3) = 25/5.5 ≈ 4.6

a3 = 10a2/(a2 + 3) = 10 x 4.6/(4.6 + 3) = 46/7.6 ≈ 6.05

a4 = 10a3/(a3+3) = 10 x 6.05/(6.05 + 3) = 60.5/9.05 = 6.685

a5 = 10a4/(a4 + 3) = 10 x 6.685/(6.685 + 3) = 66.85/9.685 ≈ 6.902

Explications étape par étape

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