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Sagot :

NEMY24

Salut!!

Explications:

SinP+SinQ=2Sin (P+q)/2Cos(P-Q)/2

F=2Sin(2x+4x)/2×cos(2x-4x)/2-2Sin3x

F=2Sin3x.Cosx-2Sin3x

F=2sin3x(Cosx-1)

F=2Sin3x(cosx-cos0)

Cosx-cos0=-2Cosx+0/2.cosx-0/2=> -2cos²x/2

F= -2×2Sin3xCos²x/2

F= -4Sin3xCos²x/2

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