Réponse :
Hello,
some corrections :
1) y = sin(x) / 5 + 2cos(x) / 5 + c / e(2x)
And c is a variable that can have any value, for example 1.
2) we choose y as the dependent variable :
y + x(dy/dx) = 0
let y' = dy/dx then we have :
y + xy' = 0
We rewrite the differential equation :
(1/y)y' = -1/x
Solving this gives us : ln(y) = -ln(x) + c
we isolate y and we finally find y = e(c) / x
or we can simply write :
y = c / x
If we have c = 1, we get the graphical representation of the inverse function 1/x.
Good Luck
