MAE971PEDU
Answered

EXERCICE 3.4
Développer puis réduire :
A = (x + 3)(x - 2) B = (x-4)(x + 6)
A = x2 - 2x + 3x - 6 B=
A = x2+x-6
B=(x-4)(x+6)
B=
B=
C = (a - 5)(2a - 7)
C=
C=
D = (4 - x2)(x + 3)
D =
D =
E = (3x-2)(5x + 1)
E=
E=
F = (4 - 2x)(-1 - 3x)
F =
F =
G = (x + 3)(x + 3)
G=
G=
H = (2-x)(2 - x)
H=
H =
I=(a+b)(a-b)
I=
I=
J = (x + 6)2
J=
J=
Bonjour pouvez vous m aider s il vous plait merci​

Sagot :

KAVITHA01

Réponse:

Bonjour,

B=(x-4)(x+6)

B=x²+6x-4x-24

B=x²+2x-24

C = (a - 5)(2a - 7)

C=2a²-7a-10a+35

C=2a²-17a+35

D = (4 - x²)(x + 3)

D=x+12-x³-3x²

D=-x³-3x²+4x+12

E = (3x-2)(5x + 1)

E = (3x-2)(5x + 1)E=15x²+3x-10x-2

E=15x²-7x-2

F = (4 - 2x)(-1 - 3x)

F = (4 - 2x)(-1 - 3x)F =-4-12x+2x+6x²

F =6x²-10x-4

G = (x + 3)(x + 3)

G=x²+3x+3x+9

G=x²+6x+9

H = (2-x)(2 - x)

H=4-2x-2x+x²

H=x²-4x+4x

I=(a+b)(a-b)

I=a²-ab+ab-b²

I=a²-b²

J = (x + 6)²

J =x²+6

J=x²+36

PAU64

Bonsoir ! ;)

Réponse :

B = (x - 4) (x + 6)

B = x * x + x * 6 - 4 * x - 4 * 6

B = x² + 6x - 4x - 24

B = x² + 2x - 24

C = (a - 5) (2a - 7)

C = a * 2a + a * (- 7) - 5 * 2a - 5 * (- 7)

C = 2a² - 7a - 10a + 35

C = 2a² - 17a + 35

D = (4 - x²) (x + 3)

D = 4 * x + 4 * 3 - x² * x - x² * 3

D = 4x + 12 - x³ - 3x²

⇔ D = - x³ - 3x² + 4x + 12

E = (3x - 2) (5x + 1)

E = 3x * 5x + 3x * 1 - 2 * 5x - 2 * 1

E = 15x² + 3x - 10x - 2

E = 15x² - 7x - 2

F = (4 - 2x) (- 1 - 3x)

F = 4 * (- 1) + 4 * (- 3x) - 2x * (- 1) - 2x * (- 3x)

F = - 4 - 12x + 2x + 6x²

F = 6x² - 10x - 4

G = (x + 3) (x + 3)

G = x * x + x * 3 + 3 * x + 3 * 3

G = x² + 3x + 3x + 9

G = x² + 6x + 9

H = (2 - x) (2 - x)

H = 2 * 2 + 2 * (- x) - x * 2 - x * (- x)

H = 4 - 2x - 2x + x²

H = x² - 4x + 4

I = (a + b) (a - b)

I = a * a + a * (- b) + b * a + b * (- b)

I = a² - ab + ab - b²

I = a² - b²

J = (x + 6)²

( rappel : (a + b)² = a² + 2 * a * b + b² ! )

J = x² + 2 * x * 6 + 6²

J = x² + 12x + 36