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[tex]bonjour,\\\\\\4 x - 1 = 2 - 5 x \\4 x + 5 x = 2 + 1 \\9 x = 3 \\x = 3 /9 = 1 /3\\\\1 + x^{2} = 8 \\\\x^{2} = 8 - 1 \\x^{2} = 7 \\x = \sqrt{7} ou - \sqrt{7}[/tex]

PAU64

Bonsoir ! ;)

Réponse :

a. 4x - 1 = 2 - 5x

⇒ 4x + 5x = 2 + 1

⇒ 9x = 3

⇒ x = 3 / 9

⇔ x = 1 / 3

b. 1 + x² = 8

⇒ x² = 8 - 1

⇒ x² = 7

⇒ x = [tex]\sqrt{7}[/tex]     ou     x = - [tex]\sqrt{7}[/tex]

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