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Sagot :

INDV

Bonjour voici les calculs:

(2n + 3)(3n-4) + (3n + 1)(2n +3) = 0​

(2n+3)(3n-4+3n+1)=0

(2n+3)(6n-3)=0

Quand

2n+3=0    ou 6n-3=0

2n=-3             6n=3

n=-3/2            n=3/6

n=[tex]-\frac{3}{2}[/tex]              n=[tex]\frac{1}{2}[/tex]

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