Sagot :
bjr
g(-2) = 0 => antécédent de 0 = -2
f(x) = x² + 2x + 1 => f(2) = 2² +2*2 +1 = 9
h(x) = 3x² - 5 => h(-3) = 3*(-3)² - 5 = 22
f(x) = 2x² => f(6) = 2*6² = 72
f(x) = 4x² - 1 => f(5) = ... tu as compris
bonjour
g (0) = 3 et g ( - 2 ) = 0
antécédent de 0 = - 2
f (x) = x² + 2 x + 1
f ( 2) = 4 + 4 + 1 = 9
h ( x ) = 3 x² - 5
h ( - 3 ) = 3 ( - 3 )² - 5 = 27 - 5 = 22
f (x) = 2 x²
f(6) = 2 *36 = 72
f ( x) = 4 x² - 1
f ( 5) = 4 *5² - 1 = 100 - 1 = 99