bonjour
( 2 x + 3 ) ( x- 5 ) = 0
un des facteurs est nul
soit 2 x + 3 = 0 et x = - 3 /2
soit x - 5 = 0 et x = 5
( x + 4 ) ( 3 x - 6 ) = 0
x = - 4 ou 6/3 = 2
2 x ( 3 x - 5 ) = 0
x = 0 ou 5/3
( x + 5)² + ( x + 5 ) ( x - 1 ) = 0
( x + 5 ) ( x + 5 + x - 1 ) = 0
( x + 5 ) ( 2 x + 4 ) = 0
x = - 5 ou - 4/2 = - 2
( 5 x + 2 )² = 0
x = - 2/5
( x + 1 ) ( 5 x - 1 ) - ( x + 1 ) ( 3 x - 12 ) = 0
( x + 1 ) ( 5 x - 1 - 3 x + 12 ) = 0
( x + 1 ) ( 2 x + 11 ) = 0
x = - 1 ou - 11/2 = - 5.5
