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Sagot :

ALEXIS94E

salut

[tex](3 + 1)^{2} > 9x^{2}[/tex]

[tex]9x^{2} +6x+1 > 9x^{2}[/tex]

[tex]6x+1>0[/tex]

[tex]6x >-1[/tex]

[tex]x>-\frac{1}{6}[/tex]

SKABETIX

Bonsoir,

[tex](3x + 1) {}^{2} > 9 {x}^{2} [/tex]

[tex]9 {x}^{2} + 6x + 1 > 9 {x}^{2} [/tex]

[tex]6x + 1 > 0[/tex]

[tex]6x > - 1[/tex]

[tex]x > - \frac{1}{6} [/tex]

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