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Sagot :

SDU61

Bonjour !

a) x+3 + x-4 = 2x - 1

donc x+3 + x-4 = 0

=> 2x-1=0

=> 2x=1

=> x=1/2.

b) 2x²-5x = (2x-5)x

donc 2x²-5x = 0

=> (2x-5)x=0

=> 2x-5=0 ou x=0

=> x=0 ou x=5/2.

c) (x+1)(x-5) = 0

=> x+1=0 ou x-5=0

=> x=-1 ou x=5.

d) 4x² - 5 = 2x(3+2x)

=> 4x² - 5 = 6x + 4x²

=> -5 = 6x

=> x=-5/6.

e) (x+1)(x+2) = 2

=> x² +3x + 2 = 2

=> x² + 3x = 0

=> x(x+3) = 0

=> x=0 ou x+3=0

=> x=0 ou x=-3.

f) (3x-5)²=0

=> 3x-5=0 ou 3x-5=0

=> x=5/3.

N'hésite pas si tu as des questions :)

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