Réponse:
1.
m(C₁₂H₂₂O₁₁) = 12m(C) + 22m(H) + 11m(O)
m(C₁₂H₂₂O₁₁) = 12×2,00.10⁻²⁶ + 22×0,167.10⁻²⁶ + 11×2,67.10⁻²⁶
m(C₁₂H₂₂O₁₁) = 5,70.10⁻²⁵ kg
2.
N = m/m(C₁₂H₂₂O₁₁)
N = 5,95.10⁻³/5,70.10⁻²⁵
N = 1,04.10²² molecules
3.
n = N/Nₐ
n = 1,04.10²²/ 6,02.10²³
n = 1,73.10⁻² mol
4.
16×n = 16×1,73.10⁻²
16n = 0,277 mol
