Sagot :
Bonjour,
On donne l'expression suivante :
F = (2x + 3)² - ( x + 5)(2 x + 3)
1) Développer et réduire F.
F = (2x + 3)² - ( x + 5)(2 x + 3)
F = 4x² + 12x + 9 - (2x² + 3x + 10x + 15)
F = 4x² + 12x + 9 - 2x² - 3x - 10x - 15
F = 4x² - 2x² + 12x - 3x - 10x + 9 - 15
F = 2x² - x - 6
2) Factoriser F.
F = (2x + 3)² - ( x + 5)(2 x + 3)
F = (2x + 3) [(2x + 3) - (x + 5)]
F = (2x + 3) (2x + 3 - x - 5)
F = (2x + 3) (x - 2)
Bonjour,
1) F = (2x+3)²-(x+5)(2x+3)
= 4x²+12x+9-(2x²+3x+10x+15)
= 2x²-x-6
2) F = (2x+3)²-(x+5)(2x+3)
= (2x+3)(2x+3)-(x+5)(2x+3)
= (2x+3)[(2x+3)-(x+5)]
= (2x+3)(x-2)