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Sagot :

CANDY1523
c. BC x A’C’ = AC x BC’
Donc AC/BC = A’C’/BC’
L’angle A’BC’
d. BA x BC’ = BC x BA’
Donc BA/BC = BA’/BC’
c. AC/A’C’ = BA/BA’
Donc AC x BA’ = BA x A’C’
D’où AC/BA = A’C’/BA’

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