Réponse :
ex 15
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AB (-4 ; 4)
BC ( 3; 1)
2AB ( -8; 8)
1/2 BC ( 1,5; 0,5)
2BC - AC (7; -3)
3/5 AC ( 0,6; -3)
2.
AB ( -1 -3; 2+2)
AB( -4; 4)
BC(2+1; 3-2)
BC(3; 1)
2AB (2×-4; 2×4)
2AB( -8; 8)
1/2 BC ( 0,5×3; 0,5×1)
1/2 BC ( 1,5; 0,5)
on a AC ( 2-3; 3+2) AC ( -1; 5)
2 BC - AC ( 2×3-(-1); 2×1-5)
2BC - AC ( 7; -3)
3/5AC( 3/5×-1; 3/5×5)
3/5AC ( -0,6; 3)
Exercice 14
u + v (7-5; 0+3)
u+v(2; 3)
u-v(7+5; 0-3)
u-v(12; -3)
3w-2u(3×1-2×7; 3×(-3) - 2×0)
3w - 2u ( -11; -9)
Explications étape par étape
