Sagot :
Ex2:
1.a. La 3e de type A ² - B ² = (a+b)(a-b)
b. D = 9x²-1 = (3x+1)(3x-1)
2. a. E = 9x²+6x+1+9x²-1 = 18x²+6x
b. E = (3x+1)[(3x+1)+(3x-1)] = (3x+1)(3x+1+3x-1) = (3x+1)6x
c. 6x(3x+1)=0
6x=0 ou 3x+1=0
x=0 Ou 3x=-1
x=-1/3
S={-1/3;0}
Ex3:
1. E = 6x²-3x+10x-5+9x²-25 = 15x²+7x-30
2. 9x² - 25 = (3x+5)(3x-5)
E = (3x+5)[(2x-1)+(3x-5)]
E = (3x+5)(2x-1+3x-5)
E = (3x+5)(5x-6)
3. 3x+5=0 ou 5x-6=0
3x=-5 Ou 5x=6
x=-5/3 Ou x=6/5
S={-5/3;6/5}
Ex4:
1. x = 5
3x+1 = 3*5+1 = 15+1 = 16
(3x+1)² = (16)² = 256
(3x+1)²-4 = 256-4 = 252
2. Zoe doit choisir: (3x+1)²-4
3. a. C = (3x+1)²-2²
C = (3x+1+2)(3x+1-2)
C = (3x+3)(3x-1)
b. 3x-1=0 ou 3x+3=0
x=1/3 ou x=-1
c. Elle a choisi -1.
(3*(-1)+1)²-4 = (-3+1)² - 4 = (-2)² - 4 = 4-4 = 0
Ex 6:
1. S={-3;0}
2. a. F = 1 pour x=-2
b. (x+3)² = x²+6x+9 = F
3. a. E = 4x²+12x
b. E-F = 4x²+12x-(x²+6x+9) = 4x²+12x-x²-6x-9 = 3x²+6x-9
c. (x+3)[4x+(x+3)] = (x+3)(5x+3)
1.a. La 3e de type A ² - B ² = (a+b)(a-b)
b. D = 9x²-1 = (3x+1)(3x-1)
2. a. E = 9x²+6x+1+9x²-1 = 18x²+6x
b. E = (3x+1)[(3x+1)+(3x-1)] = (3x+1)(3x+1+3x-1) = (3x+1)6x
c. 6x(3x+1)=0
6x=0 ou 3x+1=0
x=0 Ou 3x=-1
x=-1/3
S={-1/3;0}
Ex3:
1. E = 6x²-3x+10x-5+9x²-25 = 15x²+7x-30
2. 9x² - 25 = (3x+5)(3x-5)
E = (3x+5)[(2x-1)+(3x-5)]
E = (3x+5)(2x-1+3x-5)
E = (3x+5)(5x-6)
3. 3x+5=0 ou 5x-6=0
3x=-5 Ou 5x=6
x=-5/3 Ou x=6/5
S={-5/3;6/5}
Ex4:
1. x = 5
3x+1 = 3*5+1 = 15+1 = 16
(3x+1)² = (16)² = 256
(3x+1)²-4 = 256-4 = 252
2. Zoe doit choisir: (3x+1)²-4
3. a. C = (3x+1)²-2²
C = (3x+1+2)(3x+1-2)
C = (3x+3)(3x-1)
b. 3x-1=0 ou 3x+3=0
x=1/3 ou x=-1
c. Elle a choisi -1.
(3*(-1)+1)²-4 = (-3+1)² - 4 = (-2)² - 4 = 4-4 = 0
Ex 6:
1. S={-3;0}
2. a. F = 1 pour x=-2
b. (x+3)² = x²+6x+9 = F
3. a. E = 4x²+12x
b. E-F = 4x²+12x-(x²+6x+9) = 4x²+12x-x²-6x-9 = 3x²+6x-9
c. (x+3)[4x+(x+3)] = (x+3)(5x+3)