bonsoir
F 1 (x) = - x² + 10 x + 200
F 1 ( x = 0
- x² + 10 x + 200 = 0
Δ = ( 10 )² - 4 ( - 1 *200) = 100 + 800 = 900 = 30²
x 1 = ( - 10 - 30 ) / - 2 = - 40/ - 2 = 20
x 2 = ( - 10 + 30 ) / - 2 = - 30/2 = - 15
f x) = x² - 10 x + 200
f (x) = 0
x² - 10 x + 200 = 0
Δ = ( - 10)² - 4 ( 1 * 200 ) = 100 + 800 = 900
x 1 = ( 10 - 30 ) / 2 = - 20/2 = - 10
x 2 = ( 10 + 20 ) /2 = 30/2 = 15
f (x) x² - 40 x + 400 = 0
Δ = ( - 40)² - 4 ( 1 * 400 ) = 1 600 - 1 600 = 0
Δ = 0
donc une seule solution = 40/2 = 20