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Sagot :

CAYLUS

Réponse :

Bonjour,

Explications étape par étape

1)

[tex]7x-4-(\dfrac{7}{2}(x+\dfrac{1}{7}))\\=7x-4-\dfrac{7x}{2}+\dfrac{1}{2}\\=\dfrac{7x}{2}-\dfrac{7}{2}\\=\dfrac{7}{2}(x-1)\\\\\\\bigstar \ x < 1\ \Longrightarrow\ 7x-4 < \dfrac{7}{2}(x+\dfrac{1}{7})\\\\\bigstar \ x \geq 1\ \Longrightarrow\ 7x-4 \geq \dfrac{7}{2}(x+\dfrac{1}{7})[/tex]

2)

[tex]-\dfrac{9}{5}x+\dfrac{3}{7}-(3(-\dfrac{3}{5}x-\dfrac{1}{2}))\\=-\dfrac{9}{5}x+\dfrac{3}{7}+\dfrac{9}{5}x+\dfrac{3}{2}))\\=\dfrac{3}{7}+\dfrac{3}{2}\\=\dfrac{27}{14} > 0\\\\\Longrightarrow\ -\dfrac{9}{5}x+\dfrac{3}{7}> 3(-\dfrac{3}{5}x-\dfrac{1}{2})\\[/tex]

3)

[tex]4(x-11)-(x-44)\\=4x-44-x+44\\=3x\\\\x < 0 \Longrightarrow\ 4(x-11) < x-44\\[/tex]

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