👤

Sagot :

SVANT

Réponse :

Bonjour

10 + 1,5x < 2x

10 < 2x - 1,5x

10 < 0,5x

10/0,5 < x

20 < x

x ∈ ]20; +∞[

2)

3(x-1) < 2(x+3)

3x - 3 < 2x + 6

3x-2x < 6+3

x < 9

x ∈ ]-∞; 9[

3)

6x + 5 ≤ 2x -7

6x - 2x ≤ -7 - 5

4x ≤ -12

x ≤ -12 / 4

x ≤ -3

x ∈ ]-∞; -3]

4)

x/2 + 1 < 3/5 + x

1 - 3/5 < x - x/2

5/5 - 3/5 < 2x/2 - x/2

2/5 < x/2

2×2/5 < 2×x/2

4/5 < x

x ∈ ]4/5; +∞[

Explications étape par étape

Other Questions

© 2024 IDNLearn. All rights reserved.