bonjour
f (x) = ( x + 1 )² - 36
1 ) f (x) = ( x + 1 - 6 ) ( x + 1 + 6 )
= ( x - 5 ) ( x + 7 )
2 ) f(x) = x² + 2 x + 1 - 36
= x² + 2 x - 35
3 ) f (x) = 0
( x - 5 ) ( x + 7 ) = 0 ⇔ x = 5 ou - 7
f ( x) = - 36
( x + 1 )² - 36 = - 36
( x + 1) = 0 ⇔ x = - 1
f ( x) = - 35
x² + 2 x - 35 = - 35
x² + 2 x = 0
x ( x + 2 ) = 0 ⇔ x = 0 ou - 2
