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Sagot :

ELIEGEBRAEL68
A)xOy=xOz-yOz=180*-38*=142*
B)xOy=xOz-yOz=90*-28*=62*
C)xOy=zOy-xOz=132*-90*=42*
D)zOx=yOt=52* et xOy=zOt-zOx+yOt=180-(52+52)=180-54=126*
IMANEFERRAHQC

Réponse :

a. 180° - 38°= 142°

b. 90° - 28°= 62°

c. 132° - 90°= 42°

d. 180° - 52°=128°

voila

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