Bonsoir,
36-(4-3x)² = 6²-(4-3x)²
= [6+(4-3x)][6-(4-3x)]
= (10-3x)(2+3x)
(x+1)²-(2x+3)² = [(x+1)+(2x-3)][(x+1)-(2x+3)]
= (x+2x+1-3)(x-2x+1-3)
= (3x-2)(-x-2)
= -(3x-2)(x+2)
Réponse :
36-(4-3x)² = 6²-(4-3x)²
= [6+(4-3x)][6-(4-3x)]
= (10-3x)(2+3x)
(x+1)²-(2x+3)² = [(x+1)+(2x-3)][(x+1)-(2x+3)]
= (x+2x+1-3)(x-2x+1-3)
= (3x-2)(-x-2)
= -(3x-2)(x+2)