bonjour
| 5 x - 3 | = x + 1
| 5 x - 3 | = 5 x - 3 si 5 x ≥ 0 ⇔ 5 x ≥ 3 ⇔ x ≥ 3/5
| 5 x - 3 | = - ( 5 x - 3 ) dans le cas contraire
x - ∞ 3/5 + ∞
| 5 x - 3 | - ( 5 x - 3 ) 0 5 x - 3
- ( 5 x - 3 ) = x + 1
- 5 x + 3 = x + 1
- 5 x - x = 1 - 3
- 6 x = - 2
x = 2/6 = 1/3
5 x - 3 = x + 1
5 x - x = 1 + 3
4 x = 4
x = 1
S ( 1/3 ; 1 )
