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Sagot :

Bonjour,

[tex](x^2 + 1)(5-10x) < 0[/tex]

[tex]x^2 + 1 < 0\\5 - 10x > 0[/tex]

[tex]x^2 + 1 > 0\\5 - 10x < 0[/tex]

x ∈ ∅

x < [tex]\frac{1}{2}[/tex]

x ∈ IR

x > [tex]\frac{1}{2}[/tex]

x ∈ ∅

x ∈ [tex](\frac{1}{2} ; +[/tex]∞ )

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