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Sagot :

AYUDA

bjr

(3x+8)² - 64

= (3x)² - 2*3x*8 - 64 = 9x² - 48x - 64

= (3x+8)² - 8² = (3x+8+8) (3x+8-8) = 3x(3x+16)

donc résoudre 3x(3x+16) = 0

soit 3x = 0 => x =0

soit 3x+16 = 0 => x = -16/3

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