1) Q: (9x²-12x+4)(x+3)=0
9x²-12x+4=0
∆= (-12)²-4*9*4=0
x=12/18=2/3
x+3=0
x=-3
S={-3; 2/3}
2) (3-x)(4x+1)(3x+2)= (12x+3-4x²-x)(3x+2)
= -12x³-8x²+33x²+22x+9x+6
= -12x³+25x²+31x+6
3) -12x³+25x²+31x+6=0
3-x=0
x=3
4x+1=0
x=-1/4
3x+2=0
x=-2/3
S={-2/3; -1/4; 3}
