Sagot :
a) f(x) = 3x²+12x+8 a = 3 b = 12 c = 8
b) g(x) = 3x²+3 a = 3 b = 0 c = 3
c) k(x) = -x²+ 2x - 2/3 a = -1 b = 2 c = -2/3
d) l(x) = -x²-2x-3 a = -1 b = -2c = -3
forme canonique fonction 2nd degré : ax²+bx+c
a) f(x) = 3(x+2)²-4=3(x²+4x+4)-4=3x²+12x+12-4=3x²+12x+8 => a=3 b=12 c=8
b) g(x) = 3x²+3 => a=3 b=0 c=3
c) k(x) = -(x-1)²+1/3=-(x²-2x+1)+1/3=-x²+2x-1+1/3=-x²+2x-2/3 => a=-1 b=2 c=-2/3
d) l(x) = -2-(x+1)²=-2-(x²+2x+1)=-2-x²-2x-1=-x²-2x-3 => a=-1 b=-2 c=-3