1.) (x-3)² - (2 - 5x) (x - 3)=x²-6x+9-(2x-6-5x²+15x)=6x²-23x+15
6x² - 23x + 15
(x - 3) (6x - 5)=6x²-5x-18x+15=6x²-23x+15
2) f(5/2)=6(5/2)-23(5/2)+15=15-115/2+15=-55/2
f((V2)=6(V2)-23(V2)+15
f(0)=6(0)-23(0)+15=15
3)
6x²-23x+15=15
6x²-23x=0
x(6x-23)=0
x=0
6x=23
x=23/6
b)f(x)=0
(x-3)(6x-5)=0
x-3=0
x=3
6x-5=0
x=5/6