Sagot :
-3x-5x=2+7
-8x=9
x=-8/9
5x/2-2x/3-x/3=-5/3 -(x-7)(5x+2)=0
5x/2-3x/3=-5/3 -(5x²+2x-35x-14)=0
5x/2-x=-5/3 -5x²-2x+35x+14=0
3x/2=-5/3 -5x²+33x+14 =0
9x=-10
x=-10/9
-8x=9
x=-8/9
5x/2-2x/3-x/3=-5/3 -(x-7)(5x+2)=0
5x/2-3x/3=-5/3 -(5x²+2x-35x-14)=0
5x/2-x=-5/3 -5x²-2x+35x+14=0
3x/2=-5/3 -5x²+33x+14 =0
9x=-10
x=-10/9
Bonsoir
1) [tex]3x-7=5x+2[/tex]
[tex]3x-5x=2+7\\\\-2x=9\\\\x=-\dfrac{9}{2}[/tex]
2) [tex]\dfrac{2x}{3}+\dfrac{5x}{2}=\dfrac{x}{3}-\dfrac{5}{3}[/tex]
[tex]\dfrac{4x}{6}+\dfrac{15x}{6}=\dfrac{2x}{6}-\dfrac{10}{6}\\\\4x+15x=2x-10\\\\4x+15x-2x=-10\\\\17x=-10\\\\x=-\dfrac{10}{17}[/tex]
3) [tex](x-7)(5x+2)=0\\\\x-7=0\ \ ou\ \ 5x+2=0\\\\x=7\ \ ou\ \ 5x=-2\\\\x=7\ \ ou\ \ x=-\dfrac{2}{5}[/tex]
1) [tex]3x-7=5x+2[/tex]
[tex]3x-5x=2+7\\\\-2x=9\\\\x=-\dfrac{9}{2}[/tex]
2) [tex]\dfrac{2x}{3}+\dfrac{5x}{2}=\dfrac{x}{3}-\dfrac{5}{3}[/tex]
[tex]\dfrac{4x}{6}+\dfrac{15x}{6}=\dfrac{2x}{6}-\dfrac{10}{6}\\\\4x+15x=2x-10\\\\4x+15x-2x=-10\\\\17x=-10\\\\x=-\dfrac{10}{17}[/tex]
3) [tex](x-7)(5x+2)=0\\\\x-7=0\ \ ou\ \ 5x+2=0\\\\x=7\ \ ou\ \ 5x=-2\\\\x=7\ \ ou\ \ x=-\dfrac{2}{5}[/tex]