Résoudre les équations : 

-[tex]3x - 7 = 5x + 2[/tex]

-[tex] \frac{2x}{3} + \frac{5x}{2} = \frac{x}{3} - \frac{5}{3} [/tex]

-[tex](x - 7) X (5x+2) = 0[/tex]


Sagot :

-3x-5x=2+7
-8x=9
x=-8/9

5x/2-2x/3-x/3=-5/3                                               -(x-7)(5x+2)=0
5x/2-3x/3=-5/3                                                     -(5x²+2x-35x-14)=0
5x/2-x=-5/3                                                           -5x²-2x+35x+14=0
3x/2=-5/3                                                              -5x²+33x+14 =0
9x=-10
x=-10/9
Bonsoir

1)  [tex]3x-7=5x+2[/tex]

[tex]3x-5x=2+7\\\\-2x=9\\\\x=-\dfrac{9}{2}[/tex]

2) [tex]\dfrac{2x}{3}+\dfrac{5x}{2}=\dfrac{x}{3}-\dfrac{5}{3}[/tex]

[tex]\dfrac{4x}{6}+\dfrac{15x}{6}=\dfrac{2x}{6}-\dfrac{10}{6}\\\\4x+15x=2x-10\\\\4x+15x-2x=-10\\\\17x=-10\\\\x=-\dfrac{10}{17}[/tex]

3) [tex](x-7)(5x+2)=0\\\\x-7=0\ \ ou\ \ 5x+2=0\\\\x=7\ \ ou\ \ 5x=-2\\\\x=7\ \ ou\ \ x=-\dfrac{2}{5}[/tex]