f(x)=3x²+12x-15
=3x²+12x+12-27
=3(x²+4x+4)-27
=3(x+2)²-27
f(x)=3((x+2)²-9)
=3(x+2-3)(x+2+3)
=3(x-1)(x+5)
f(x)=-15
3x²+12x-15=-15
3x²+12x=0
x²+4x=0
x(x+4)=0
x=0 ou x=-4
f(x)<=-27
3(x+2)²-27<=-27
3(x+2)²<=0
x=-2
f(x)>=21
3(x+2)²-27>=21
(x+2)²>=16
(x+2-4)(x+2+4)>=0
(x-2)(x+6)>=0
x<=-6 ou x>=2