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Sagot :

b=(1/3x-1) (1/3x+2)
=1/9x²+2/3x-1/3x+2
=1/9x²+1/3x+2
(1/3x-1)(1/3x+2) = [tex] \frac{1}{9} x^{2} + \frac{2}{3} x - \frac{1}{3} x -2[/tex]=[tex] \frac{1}{9} x^{2} + \frac{1}{3} x-2 [/tex]
[tex] \frac{1}{9} x^{2} + \frac{1}{3} x-2 [/tex]=0 ,
delta = ([tex] \frac{1}{3} ^{2} - 4* \frac{1}{9}*(-2)[/tex]= [tex] \frac{1}{9} + \frac{8}{9} = 1[/tex]
[tex] \sqrt{delta}= \sqrt{1} =1[/tex]
x= [tex]- \frac{1}{3} -1: 2* \frac{1}{9} = - \frac{4}{3}: \frac{2}{9} = -6[/tex]
x= [tex]- \frac{1}{3} +1: 2* \frac{1}{9}= \frac{2}{3}: \frac{2}{9}= 3[/tex]




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