Sagot :
x-7 = ( 1+x) * (2-x)
x-7 = 2 - x + 2x - x exp 2
x-x-9 = - xexp2
-9 = - xexp2
9 = xexp 2
x =3
x-7 = 2 - x + 2x - x exp 2
x-x-9 = - xexp2
-9 = - xexp2
9 = xexp 2
x =3
[tex] \frac{x-7}{2-x} = 1+x
\frac{x-7}{2-x} = \frac{(1+x)(2-x)}{1(2-x)}
x-7 = 2-x+2x-x²
x+x-2x+x² = 2+7
x²= 9
x= \sqrt{9}
x= 3[/tex]
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