Programme A
-3 (x -10) - 2x, soit -3x+10-2x = 10 - 5x
Si x = 5 -> on a -15
Si x = -20 -> on a 110
Si x = 100 -> on a -490
Programme B
-6 (x - 5) + x, soit -6x+30+x = 30 - 5x
Si x = 5 -> on a 5
Si x = -20 -> on a 130
Si x = 100 -> on a -470
On en déduit que, quel que soit x, B=A+20
