Answered

Calculer pour x=3
         2
E= 4[tex] x^{2} [/tex] -5x+2


        2      
F=-3+4x+1

developper et reduire

a=5(2x+1)+3(x+4)

b=-2(-3x-5)-4(x-7)

c=(x+1)(x+5)

d='2x-3)(-x+4)

e=-5(2x-3)+2x-1)(x-3)

f=(2x-3)(-x-1)-x(2x+5)

Sagot :

x=3
E = 4x²-5x+2
   =4(3)²-5(3)+2
   =4(9)-15+2
   =36-15+2=23
F = -3+4x+1
   =-3+4(3)+1
   =-3+12+1=10
2(2x+1)+3(x+4)
4x+2+3x+12
7x+14

-2(-3x-5)-4(x-7)
6x+10-4x+28
2x+38

(x+1)(x+5)
x²+5x+x+5
x²+6x+5

(2x-3)(-x+4)
-2x²+8x+3x-12
-2x²+11x-12

-5(2x-3)+(2x-1)(x-3)
-10x+15+2x²-6x-x+3
2x²-17x+18

(2x-3)(x-1)-x(2x+5)
2x²-2x-3x+3-2x²-5x
-10x+3