Bonjour
N(x) = 50-x ( exprimée en milliers )
1)
C(x) = 200+5x
2)
R(x) = N(x) * x = (50-x)x = 50x - x²
3)
B(x) = R(x) -C(x)
B(x) = (50x-x²) - (200+5x)
B(x) = -x²+45x-200
4a)
Bénéfice maximal pour x = -b/2a = -45 / -2 = 22.5
B(22.5) = 506.25+1012.50-200 = 306.25
B(x) = 0
-x²+45x-200 = 0
delta = b²-4ac = 1225
Vdelta = V1225 = 35
deux solutions
x' = (-45-35)/-2 = 40
x" = (-45+35)/-2 = 5
B(x) >0 pour 5 < x < 40