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Sagot :

B+ 2A = 20
2B + C = 20
2A + 2C = 20
3A + D= 20
donc

B+ 2A = 20
2B + C = 20
A + C = 10
3A + D= 20

donc

B+ 2A = 20
2B - A = 10
A + C = 10
3A + D= 20

donc
B+ 2A = 20
4B - 2A = 20
A + C = 10
3A + D= 20

donc
5B=40
2B - A = 10
A + C = 10
3A + D= 20

donc
B=8
A=2B-10
C=10-A
D=20-3A
donc
A=6
B=8
C=4
D=2



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