f(3) = 2/3 (3) + 1 = 6/3 + 1 = 2+1 = 3
f(-3) = 2/3*(-3) + 1 = -6/3 + 1 = -2+1 = -1
f(-1) = 2/3*(-1) + 1 = -2/3 + 1 = -2+3/3 = 1/3
f(3/4) = 2/3*(3/4) + 1 = 6/12 + 1 = 1/2 + 1 = 3/2
pour trouver l'antécédent, il faut écrire f(x) = 1
2/3 x+1 = 1
2/3 x = 1 - 1=0
x = 0